Step-by-Step Solution

Topic: Total Probability & Bayes’ Theorem

Probability Tree Diagram

Branch 1: Person A (0.5) → Plant (0.7).
Branch 2: Person B (0.6) → Plant (0.4).

1. Define Events & Probabilities

  • • Let E1: First person is appointed. P(E1) = 0.5
  • • Let E2: Second person is appointed. P(E2) = 0.6
  • • Let A: Waste treatment plant is introduced.

Conditional Probabilities:

  • • P(A|E1) = 0.7 (Plant introduced by Person 1)
  • • P(A|E2) = 0.4 (Plant introduced by Person 2)

(I) TOTAL PROBABILITY OF PLANT INTRODUCTION

Using the Law of Total Probability:

P(A) = P(E1)P(A|E1) + P(E2)P(A|E2)

Substitute the values:

P(A) = (0.5 × 0.7) + (0.6 × 0.4)

P(A) = 0.35 + 0.24

Total Probability P(A) = 0.59

(II) PROBABILITY OF PERSON 1 (Given Plant Introduced)

We need to find P(E1|A) using Bayes’ Theorem:

P(E1|A) = [ P(E1) × P(A|E1) ] / P(A)

Substitute the values calculated in Part (I):

Numerator = P(E1)P(A|E1) = 0.5 × 0.7 = 0.35

Denominator = P(A) = 0.59

Therefore:

P(E1|A) = 0.35 / 0.59

Final Probability = 35/59 (≈ 0.593)